int a(int * p, int x)
{
int y = x + 3;
p[y] = 1;
p[y + 1] = 2;
p[y + 2] = 3;
p[y + 3] = 4;
return p[y] + p[y + 1] + p[y + 2] + p[y + 3];
}
int main(void)
int t[16];
return a(t, 4) - 10;