randr: simplify extra payload copying in ProcRRGetOutputInfo()
Make it a bit easier to understand how exactly the name string is copied into the reply payload: just do the little memcpy() right where the target position is decided any the rest of the payload is filled. Signed-off-by: Enrico Weigelt, metux IT consult <info@metux.net>
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@ -437,14 +437,12 @@ ProcRRGetOutputInfo(ClientPtr client)
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REQUEST(xRRGetOutputInfoReq);
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xRRGetOutputInfoReply rep;
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RROutputPtr output;
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CARD8 *extra;
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unsigned long extraLen;
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ScreenPtr pScreen;
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rrScrPrivPtr pScrPriv;
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RRCrtc *crtcs;
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RRMode *modes;
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RROutput *clones;
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char *name;
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int i;
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Bool leased;
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@ -456,6 +454,8 @@ ProcRRGetOutputInfo(ClientPtr client)
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pScreen = output->pScreen;
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pScrPriv = rrGetScrPriv(pScreen);
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CARD8 *extra = NULL;
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if (leased) {
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rep = (xRRGetOutputInfoReply) {
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.type = X_Reply,
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@ -473,11 +473,8 @@ ProcRRGetOutputInfo(ClientPtr client)
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extra = calloc(1, extraLen);
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if (!extra)
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return BadAlloc;
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memcpy(extra, output->name, output->nameLength);
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}
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else
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extra = NULL;
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name = (char *) extra;
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} else {
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rep = (xRRGetOutputInfoReply) {
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.type = X_Reply,
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@ -506,13 +503,12 @@ ProcRRGetOutputInfo(ClientPtr client)
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if (!extra)
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return BadAlloc;
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}
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else
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extra = NULL;
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crtcs = (RRCrtc *) extra;
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modes = (RRMode *) (crtcs + output->numCrtcs);
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clones = (RROutput *) (modes + output->numModes + output->numUserModes);
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name = (char *) (clones + output->numClones);
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memcpy((clones + output->numClones), output->name, output->nameLength);
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for (i = 0; i < output->numCrtcs; i++) {
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crtcs[i] = output->crtcs[i]->id;
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@ -533,7 +529,7 @@ ProcRRGetOutputInfo(ClientPtr client)
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swapl(&clones[i]);
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}
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}
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memcpy(name, output->name, output->nameLength);
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if (client->swapped) {
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swaps(&rep.sequenceNumber);
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swapl(&rep.length);
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